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12-04-2006
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Print lines with search string at specific position
Hi Folks,
I have a file with all fields defined by byte position, but any field can be empty so I cannot print lines based on a search of specific columns. I need to print all lines of this file where the string of two characters at byte position 100-101 contains the number 27. Any ideas? Sample file: ...abc def 987lm ...tia fer g270 ... gerta27mlonep ...ferssdfsdff22 I would print the second and third lines. Thanks 
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12-04-2006
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sorry if i'm wrong
but you want print lines where the char 100=2 and 101=7
if yes this will help you. Code:
#!/usr/bin/perl
if(@ARGV eq ""){
print "Usage = ./$0 <FILE>\n";
exit 0;
}
$fl=join(" ",@ARGV);
open(FD,"< $fl")|| die "Can't read $fl\n";
@lines=<FD>; #read the lines
close(FD);
foreach(@lines){ #dúh
@chars=split(//,$_); #get chars of a line
if($chars[99] eq "2"){ #cause arrays begin in 0
if($chars[100] eq "7"){
print "$_"; #uhh we print the line :D
}
}
}
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12-04-2006
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Code:
awk '{ if( substr($0, 2, 3) ~ /patter/ ) { print } }' file
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12-04-2006
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Python alternative:
Code:
#!/usr/bin/python
for line in open("file.txt"):
if line[99:101] == "27":
print line
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