Parsing a file in Shell Script

sendhilmani123 · #1 (**permalink**) 11-30-2006

Hi,

I have a requirement. I have an application which can take a file as inputs. Now the file can contain any number of lines. The tool has to pick up the first uncommented line and begin processing it.
For example the file could be like this:
#MANI123|MANI1234
#MANI234|MANI247
SENDIL204|SENDIL505
INPUT4|INPUT5.

Now the tool has to pick up only the third line as it is the first uncommented line i.e . SENDIL204|SENDIL505. How can I do this in a shell script

Thanks in advance

matrixmadhan · #2 (**permalink**) 11-30-2006

Code:

grep -v ^# filename

the logical first line becomes your actual first line

aju_kup · #3 (**permalink**) 11-30-2006

use

grep -v "^\#" tmp

you can pipe this output to while loop and then process accordingly

matrixmadhan · #4 (**permalink**) 11-30-2006

Quote:

grep -v "^\#" tmp

What is the need for "^\#" ?

Just "^#" would do.

aju_kup · #5 (**permalink**) 11-30-2006

i have not tried to rectify your post

i tried in my way

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