How to count the number of files in a directory.

Thanks
Mahalakshmi.A

I think this had been answered many times

only the count of files and not directories

not sure if this is efficient tho

ls -l | grep -v drw | awk '{ print $9 }' | wc -l

you are assuming r and w perm for users if its a directory,
there need not be such a perm for user.

it could be even dr-x

in that case, your condition would fail to filter

Thanks for the replies which I had got.
Can you please explain me about awk '{print $9}' in ls -l | grep -v drw | awk '{ print $9 }' | wc -l

Thanks
Maha

hi,

grep -v use filter off anything that starts with drw like directories generally start with drw

wc is word count, -l used to display number of lines

awk '{ print $9 }' prints out the 9th column of the output

when you do a ls -l it prints out some file with

col1 col2 col3 col4 col5 col6 col7 col8 col9
-rw-r--r-- 1 root other 151 Nov 15 14:28 xx
drw-r--r-- 1 oracle dba 72 Nov 15 14:36 apple

enjoy

above command shows the 9th column of the grep o/p.

ex:

suppose o/p of the above grep command
then o/p of awk command would be