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Extract digits at end of string

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#1 (permalink)

Old

11-20-2006

offirc

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Extract digits at end of string

I have a string like xxxxxx44. What's the best way to extract the digits (one or more) in a ksh script?

Thanks

#2 (permalink)

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11-20-2006

cskumar

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elaborate your question.

can u elaborate your question /provide some sample input.
what do u want to do exactly?

#3 (permalink)

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11-20-2006

Ygor

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Try...

Code:

var1="xxxxxx44"
var2=$(expr $var1 : "[^0-9]*\([0-9]*\)")

#4 (permalink)

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11-20-2006

aigles

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Extraction of the trailing digits :

Code:

var=xxxxx44
digits=${var#${var%%*([0-9])}}

Jean-Pierre

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11-20-2006

matrixmadhan matrixmadhan is offline

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how about this,

Code:

echo "abcde444" | sed 's/[a-z]//g'

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11-20-2006

aigles

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Ygor and matrixmadhan, your solutions works fine, but only if the trailing digits are prefixed by non digit characters.

For example :

Code:

var="xxx1xxx44"
expr $var1 : "[^0-9]*\([0-9]*\)"   # => Gives 1
echo $var1 | sed 's/[a-z]//g'        # => Gives : 144

Jean-Pierre.

#7 (permalink)

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11-20-2006

offirc

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Quote:

Originally Posted by matrixmadhan

how about this,

Code:

echo "abcde444" | sed 's/[a-z]//g'

Thanks - that's just what I was trying to do.

Thanks all for your replies

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