Friends, need your help in awk

I have a pattern which I need to serach and print the next line after the pattern.

PATTERN="$MON $DAT $HOUR"

part of the script is as follows :

if [ $HOUR -le 24 ]; then

echo awk "'/$PATTERN/ {print;getline;print;}'" text.txt
awk "'/$PATTERN/ {print;getline;print;}'" text.txt
fi

when I echo the awk command :
echo awk "'/$PATTERN/ {print;getline;print;}'" text.txt
the command looks perfect from the echo :
awk '/Nov 13 13/ {print;getline;print;}' text.txt

But ,the next command :
awk "'/$PATTERN/ {print;getline;print;}'" text.txt

gives an error,
awk: syntax error near line 1
awk: bailing out near line 1

Would appreciate if you guys can help me out

Remove the simple quotes :

awk "/$PATTERN/ {print;getline;print;}" text.txt

Thanks a lot Jean .. appreciate your help :-)