Hi,

If I have 90 lines and I want to print the 45th line, is there a quick sed command for this?

thx.

sed2liners

# print line number 52
 sed -n '52p'                 # method 1
 sed '52!d'                   # method 2
 sed '52q;d'                  # method 3, efficient on large files

Thanks, but would if I did not know the middle line number?

Is there a formula to figure out the middle line number?

Something like (wc -l) divided by 2 ?

thx.

echo `wc -l filename| cut -f 1 -d " "`/2 | bc

echo `wc -l filename| cut -f 1 -d " "`/2 | bc
syntax error on line 1, teletype

Thanks for the replies, but I can't get it to work. The file is a list of names:

Frank
Sally
Sam
Julie
Joe
Jay
Ralph
John
Sally
Fred
Sue

word count(lines) is 11

I need to print the middle line which is 'Jay' which is the middle (6th) line.

thx.

Don't know which would be faster, but..

# cat names
Frank
Sally
Sam
Julie
Joe
Jay
Ralph
John
Sally
Fred
Sue
# awk '{ lines[NR]=$0; } END { print lines[int(NR/2)+1] }' names
Jay
#