xor 2 values in ksh?

DukeNuke2 · #1 (**permalink**) 11-08-2006

i have to xor two variables in ksh. how to do that?

tia,
DN2

tmarikle · #2 (**permalink**) 11-08-2006

It's easier done with Perl:

Code:

perl -le 'print (16 ^ 5)'
21

perl -le 'print (21 ^ 5)'
16

DukeNuke2 · #3 (**permalink**) 11-08-2006

perl is no option.... its not on all systems

tmarikle · #4 (**permalink**) 11-08-2006

Quote:

Originally Posted by DukeNuke2

perl is no option.... its not on all systems

Sorry, my bad. This can be done with KSH using built in operations (I haven't really had a need for this to date).

Code:

print $(( 16 ^ 5 ))
21

print $(( 21 ^ 5 ))
16

DukeNuke2 · #5 (**permalink**) 11-08-2006

Quote:

Originally Posted by tmarikle

Sorry, my bad. This can be done with KSH using built in operations (I haven't really had a need for this to date).

Code:

print $(( 16 ^ 5 ))
21

print $(( 21 ^ 5 ))
16

this works... thank you so much!

aigles · #6 (**permalink**) 11-08-2006

A possible solution:

Code:

a=15
b=10
a_xor_b=$(perl -e "print $a^$b")     <- gives 5

Jean-Pierre.

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