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10-31-2006
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awk script to find the number of files
awk script to find the number of files in a directory with their date less than 15-oct-2006
please help 
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10-31-2006
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no technical reason as such.
even a awk command on the prompt line would do
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10-31-2006
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Why you don't you use find, like this:
Code:
#Create a file with a datestamp of 15 Oct, 2006 first touch -t 200610150000.00 test #Find the files newer than 'test' and redirect the output to test1 file find . -type f -newer test -print > test1 #Count the number of lines in 'test1' file, this is what you want wc -l test1
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