Write a shell program to find the sum of alternate digits in a given 5-digit number

banta · #1 (**permalink**) 10-29-2006

Hi Can any one please post the answer for the above program..................

vgersh99 · #2 (**permalink**) 10-29-2006

banta.sh 28462

banta.sh:

Code:

#!/bin/ksh

a="${1}"

typeset -i i=1

while (( i <= 5 ))
do
  ((num=$(echo "${a}" | cut -c "${i}") ))
  if (( i == 1 )); then
     printf "$num"
  else
     printf "+$num"
  fi
  ((sum=sum + num))
  ((i=i+2))
done

printf "=${sum}\n"

ghostdog74 · #3 (**permalink**) 10-29-2006

Python alternative

Code:

#!/usr/bin/python
a = 12345
b = list(str(a))
print sum( map(int,b[::2]) )

output:

Code:

rajnikanth.1912 · #4 (**permalink**) 10-30-2006

You need to initialise the variables num and sum

#!/bin/ksh

a=12346
b=`expr length $a`
echo " length : $b"
typeset -i i=1
num=0
sum=0
while (( i <= $b ))
do
((num=$(echo "${a}" | cut -c "${i}") ))
if (( i == 1 )); then
printf "$num"
else
printf "+$num"
fi
((sum=sum + num))
((i=i+2))
done
printf "=${sum}\n"
~

Answer
-------
length : 5
1+3+6=10

blowtorch · #5 (**permalink**) 10-30-2006

Er... obvious example of homework? Thread closed.

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