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10-19-2006
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Need help to create a date script
So I need to create a shell script that can take as input a numeric day, month and year and output the day of the week for the input date.
So let's say, I input "programname 19 10 2006" it should output Thursday... I tried messing around with the grep and awk commands, but I can't get it to work. I'd appreciate any help. 
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10-19-2006
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Use Perderabo's datecalc script -- http://www.unix.com/showthread.php?s...6559#post16559. It's as easy as:
Code:
> datecalc -D 1960 12 31 Saturday
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10-19-2006
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So I tried to run the script named it Zoltar...
[elee@uxprod elee]$ bash Zoltar -D 1960 09 09 Zoltar: line 116: integer: command not found Zoltar: line 81: integer: command not found Zoltar: line 83: set: -A: invalid option set: usage: set [--abefhkmnptuvxBCHP] [-o option] [arg ...] Zoltar: line 91: ((: 09: value too great for base (error token is "09") Zoltar: line 96: ((: 09: value too great for base (error token is "09") Zoltar: line 110: print: command not found Zoltar: line 123: ((: 09: value too great for base (error token is "09") Zoltar: line 131: ((: 09: value too great for base (error token is "09") Zoltar: line 135: print: command not found Zoltar: line 142: integer: command not found Zoltar: line 143: set: +A: invalid option set: usage: set [--abefhkmnptuvxBCHP] [-o option] [arg ...] Zoltar: line 154: print: command not found
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10-19-2006
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datecalc uses ksh. Just chmod +x the datecalc script and run it as
Code:
datecalc -D 1960 12 31
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10-19-2006
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Python alternative
Code:
import sys,time
day,month,year = sys.argv[1:] #assume first param is day, then month, finally year
b = time.strptime("%s %s %s" % (day ,month, year), "%d %m %Y")
convert = time.strftime("%A", b)
print convert
Code:
/home> python test.py 19 10 2006 Thursday
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