need help with simple awk/ksh script

tefflox · #1 (**permalink**) 09-27-2006

I need help finding out why this script wont run. The chmod is okay, but i get an error saying that I need '&&' on line 5.

Quote:

#! /bin/ksh

read x

for file in 'ls -al | awk '$6 == "Sep" && $7 < 18 , $6 != "Sep"'

do

mv $file ~/compressed.tar/$file
read x

done

tar -cvf compressed.tar

Andrek · #2 (**permalink**) 09-27-2006

I think you missing a single quote '

tefflox · #3 (**permalink**) 09-27-2006

it still says i need '&&' on line 5... does everything else look right?

tefflox · #4 (**permalink**) 09-27-2006

here is how it looks now

Quote:

#! /bin/ksh

read x

for file in 'ls -al | awk '$6 == "Sep" && $7 < 18''

do

mv $file ~/compressed.tar/$file
read x

done

for file in 'ls al | awk '$6 != "Sep"''

do

mv $file ~/compressed.tar/$file
read x

done

tar -cvf compressed.tar

hitmansilentass · #5 (**permalink**) 09-27-2006

try this

Code:


#! /bin/ksh
read x

for file in `ls -al | awk $6 == "Sep" && $7 < 18''`
do
mv $file ~/compressed.tar/$file
read x
done

for file in 'ls al | awk '$6 != "Sep"''
do
mv $file ~/compressed.tar/$file
read x
done

tar -cvf compressed.tar

Anyways, what are you trying to achive here??

tefflox · #6 (**permalink**) 09-27-2006

i get

Quote:

mv: 18 not found

mv: "Sep" not found

tar: Missing filenames

but no more '&&' needed in line 5... thanks for helping.

hitmansilentass · #7 (**permalink**) 09-27-2006

Oops try this

Code:

read x

for file in `ls -al | awk '{$6 == "Sep" && $7 < "18"}'`
do
mv $file ~/compressed.tar/$file
read x
done

for file in 'ls al | awk '{$6 != "Sep"}'
do
mv $file ~/compressed.tar/$file
read x
done

tar -cvf compressed.tar sourcefilename

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