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#1
09-14-2006
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Regular expression query in AWK
I have a varable(var1) in a AWK script that contain data in the following format
[timestamp] [priority] - [log message] I need to extract timestamp,priority and log message.I can extract these by using split function but i don't want to use it, since i want to extract it in one go. I have some difficulties in doing it using Regular expression using a single statement. Can anybody help me on this 
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#2
09-15-2006
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Try...
Code:
awk 'BEGIN{
var = "[timestamp] [priority] - [log message]"
n = split(var, arr, /(^\[)|(\] -? ?\[)|(\]$)/)
for (x=2; x<n; x++)
printf "arr[%d]=%s\n", x, arr[x]
}'
Code:
arr[2]=timestamp arr[3]=priority arr[4]=log message
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#4
09-15-2006
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