Please help! Sed extract a pattern

zhen · #1 (**permalink**) 09-14-2006

I am trying to extract "securitySettings" out of line:

<a ref ="http://localhost:5654/securitySettings">

using sed as follows:

name = `grep "localhost" file.html | sed -n 's/.*[0-9]*\/\(.*)/\">/\1/p'`

But it didn’t run, seems have some syntax error. Do anybody knows why?

Thank you very much!

anbu23 · #2 (**permalink**) 09-14-2006

you missed \ in $.*$
unnecessary / in /\">/\1/p
after those modifications

Code:

sed -n 's/.*[0-9]*\/\(.*\)">/\1/p'

fedora · #3 (**permalink**) 09-14-2006

emmmm, why this did not work? it has a ">" at the end of output

$ sed 's/^.*:[0-9][0-9]*\/$[^\"]*$\"\>/\1/' /tmp/test
securitySettings>

reborg · #4 (**permalink**) 09-14-2006

Code:

sed -n 's_.*/\([^/]*\)">_\1_p'

sayonm · #5 (**permalink**) 09-15-2006

can be don in a much more simpler way as follows(i mean there is lesser chance of getting lost in sed

)

Code:

grep "loaclhost" file.html | awk -F'/' '{print $NF }' | sed -e 's/>//g'

hope his works.........do let us know

ghostdog74 · #6 (**permalink**) 09-15-2006

Quote:

Originally Posted by zhen

I am trying to extract "securitySettings" out of line:

<a ref ="http://localhost:5654/securitySettings">

using sed as follows:

name = `grep "localhost" file.html | sed -n 's/.*[0-9]*\/\(.*)/\">/\1/p'`

But it didn’t run, seems have some syntax error. Do anybody knows why?

Thank you very much!

hi , can i clarify , you just want to get "securitySettings" from a line and then assign the value "securitySettings" to a variable called "name" ?

Code:

grep "securitySettings" file.html
if [ $? -eq 0 ]; then
   name='securitySettings'
fi

I think i am missing something...

sayonm · #7 (**permalink**) 09-15-2006

Quote:

Originally Posted by ghostdog74

hi , can i clarify , you just want to get "securitySettings" from a line and then assign the value "securitySettings" to a variable called "name" ?

I think i am missing something...

he doesnt want to search for securitySettings. Instead he wants to search the word "localhost" and find the last part of that link(href as in a html tag)...

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