HELP PLS!! Shell Scripting!!

Mary_xxx · #1 (**permalink**) 09-14-2006

Dear All,

forgive me as i am a complete beginner in shell scripting in UNIX.

I have a file with data similair to the following

8 McDonalds Sandwich 1.99
9 Mcdonalds Fries 1.20
13 McDonalds Milkshake 1.20
7 KFC Fillet Tower 2.50
15 KFC Fries 1.00
3 Burger King Whopper 2.99
14 Burger King Fries 1.40
17 Burger King Soda 1.60

I want to arrange this file so instead of the above, the information is shown in the following pattern;

McDonalds

Fries 9 1.20
Sandwich 8 1.99
Milkshake 13 1.20

And so on for KFC & Burger King ...

what is important is the way McDonalds is now as a heading with its menu being summarised.

Sorry if i havnt explained this well!!

Please can sum1 help me?
I know it involves writing a script in awk or sed but not sure how to start.
Major thanks in advance thank u

Mary

anbu23 · #2 (**permalink**) 09-14-2006

Code:

awk ' { if ( nm != to_lower($2) { nm=to_lower($2);print nm }
          printf("%s",$1)
          for( i = 3; i <= NF ; ++i )
                printf(" %s",$i)
          printf("\n")
}' file

jim mcnamara · #3 (**permalink**) 09-14-2006

Or:

Because your data has no conclusive way to tell fields apart, you need to
add field sep characters. I used | - without this you would have to resort
to a huge nest of if-then-else logic, because you want to rearrange by what
amounts to a single number column then a multi-column value (1..2)

data

Code:

8 |McDonalds| Sandwich| 1.99
9 |McDonalds| Fries |1.20
13|McDonalds| Milkshake 1.20
7 |KFC| Fillet Tower |2.50
15|KFC| Fries |1.00
3 |Burger King| Whopper |2.99
14|Burger King| Fries |1.40
17|Burger King| Soda |1.60

Code:

 awk -F'|' '{if($2!=old) {print $2; old=$2}
             print $3,$1,$4
            }' filename

output

Code:

McDonalds
 Sandwich 8   1.99
 Fries  9  1.20
 Milkshake 1.20 13 
KFC
 Fillet Tower  7  2.50
 Fries  15 1.00
Burger King
 Whopper  3  2.99
 Fries  14 1.40
 Soda  17 1.60

Anbu does your code produce this output?

anbu23 · #4 (**permalink**) 09-14-2006

It wont produce that output.

nervous · #5 (**permalink**) 09-16-2006

Hi Anbu23,

Can you pls explain the following awk code:

Code:

awk ' { if ( nm != to_lower($2) { nm=to_lower($2);print nm }
          printf("%s",$1)
          for( i = 3; i <= NF ; ++i )
                printf(" %s",$i)
          printf("\n")
}' file

Thanks in advance.

ghostdog74 · #6 (**permalink**) 09-16-2006

alternative in Python:

Code:


#assume known data of food provider.
data = ['McDonalds' , 'KFC' , 'Burger King']
basket = {} #to store results

def insert(dictionary,key,val):
    if dictionary.has_key(key):
      dictionary[key].append(val)
    else:
      dictionary[key] = [val]

for items in data:      
	for lines in open("inputfile.txt"):
		splitted = lines.split(" ")		
		qty,middle,price = splitted[0], ' '.join(splitted[1:-1]), splitted[-1]	
		if items in middle:			
			food = middle[len(items):] #eg get Fries, Whopper
			insert(basket,items, ' '.join([food,qty,price]))
			
for i in sorted(basket.keys()):
	print i
	print " " + ' '.join(basket[i])
	print

Output:

Code:

/home> python test.py
Burger King
  Whopper 3 2.99
  Fries 14 1.40
  Soda 17 1.60

KFC
  Fillet Tower 7 2.50
  Fries 15 1.00


McDonalds
  Sandwich 8 1.99
  Fries 9 1.20
  Milkshake 13 1.20

sayonm · #7 (**permalink**) 09-16-2006

Code:

for ((i=1;i<=`awk -F'|' '{print $2}' file | uniq | wc -l`;i++))
do
        word=`awk -F'|' '{print $2}' file | uniq |head -$i | tail -1`
        echo $word
        grep "$word" file | awk -F'|' '{print $3,$1,$4}'
done

the output is as follows:-

Code:

[sayonm@zion ~]$ sh script.sh
McDonalds
 Sandwich 8   1.99
 Fries  9  1.20
 Milkshake 13  1.20
KFC
 Fillet Tower  7  2.50
 Fries  15 1.00
Burger King
 Whopper  3  2.99
 Fries  14 1.40
 Soda  17 1.60

NOTE: assumed that the file was delimited by "|"
cheers,
Sayon

ps: edited previous post

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