return code not captured - Shell Programming and Scripting

ranj@chn · #1 09-05-2006

Hi all,
We have a script in our Unix box(HP-UX 11.11) which is invoked as

Code:

script1.sh param1 param2 >>${logfile}               script2.sh "param"

Actually the script2 is also called from the same line. There is no semicolon between the 2 calls. I also checked the octal dump. What happens here is that the return code of the script1 is checked in script2. 2-3 days back, script1 failed but script2 didnt catch the error.

What I would like to know is whether this is a valid syntax? And why the script2 doesnt catch the error? Any suggestions would be very helpful.

Regards,
Ranj

jim mcnamara · #2 09-05-2006

Code:

possibilities:
script1.sh param1 param2 >>${logfile}  ||             script2.sh $? "param"
script1.sh param1 param2 >>${logfile}     &&          script2.sh "param"

Normally, if you want script2 to "see" previous error status you have to pass status to it or have the shell intervene. The only other possibility is to have script1 write status to a file. Then script2 reads the file.

ranj@chn · #3 09-06-2006

Thanks Jim. So, the above syntax is wrong then. I will work the suggestions and come back later.

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