How to cut last 10 digits off

psarava · #1 (**permalink**) 08-28-2006

Hi I'm new to this. I need to cut off the last 10 digits from a line.
I've used awk {'print $4'} filename.txt | cut -c 32-42 but this does not guarantee only the last 10 characters.

Please help. Thanks.

Sara

vish_indian · #2 (**permalink**) 08-28-2006

Quote:

Originally Posted by psarava

Hi I'm new to this. I need to cut off the last 10 digits from a line.
I've used awk {'print $4'} filename.txt | cut -c 32-42 but this does not guarantee only the last 10 characters.

Please help. Thanks.

Sara

If you are using BASH as shell. This would work.

Code:

while read line; do echo ${line:(-10)}; done < filename

Another way using awk(gawk)

Code:

awk '{LEN=length($0);print substr($0,LEN-9)}' filename

Klashxx · #3 (**permalink**) 08-28-2006

Other way:

Code:

hl=${#line}   
ll=$(( hl - 10 ))
echo ${line}|cut -c-${ll}-${hl}

tayyabq8 · #4 (**permalink**) 08-28-2006

One otherway:

Code:

echo $line | awk '{print substr($0, length($0)-9)}'

psarava · #5 (**permalink**) 08-29-2006

Thanks guys. They all work. You guys are really good.

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