Hi,
Is there any function in Unix that could get the Time Differrence of two values? this would be used as statistic for how long a job completes, from start to finish..

Please help.

thanks,
Jet

# time find / -name host*
....
....
....

real 0m12.63s
user 0m1.82s
sys 0m8.44s

#

Thanks..
Could you explain what the code do?

time <some command> - does what you want, return elapsed times
find / -name 'host*' - searches for all filenames on the system that start with "host"

Is there any way to find a execution time of a shell script which have number of commands?

If you're asking what I think you are, it's time ./shell-script.sh

Or if you're asking for something that tells how many commands the shell script has executed, only the shell script knows.

Thanks for your reply. i know this time command but i need to make it in that shell script only.Like if shell script have n number of commands then need time as sum of time taken by all the commands.any help would be appreciated.