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  #1  
Old 08-09-2006
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Join Date: Jul 2006
Posts: 183
Help with the script

I have a script where I pass some part of the file as parameter and also along with another parmater that says whether it's daily or monthly file. I check to see if the file is DLY then I get a NEW_DT from another file. After i get the NEW_DT I have to check if in the directory there are files with the name of the file I passed as parmater along with the NEW_DT. If the number of files are equal to 2 then I have to do futher processing. I am not getting where I am wrong. Please correct me.

Quote:
#!/bin/ksh
export FILENAME=$1
export FILETYPE=$2

export STG_LOG_DIR='/edwstage/Logs'
dev='/biddf/ab6498/dev/ctl'
cd $dev

if [ $2 = 'DLY' ]; then
export RUNDTFILE=audt_run_dt_dly.txt
else
export RUNDTFILE=audt_run_dt_mth.txt
fi

export OLD_DT=`grep OLD_DT $STG_LOG_DIR/$RUNDTFILE | cut -f2 -d':'`
export NEW_DT=`grep NEW_DT $STG_LOG_DIR/$RUNDTFILE | cut -f2 -d':'`

myfilepattern=$1
fullpattern=${myfilepattern}_???_$NEW_DT.dat
integer filecount=0
for file in $fullpattern ; do
[ "$file" = "$fullpattern" ] && filecount=$filecount+1
done

if (( $filecount == 2 )); then
print "success"
exit 0
else
print "failure"
exit 1
fi
I call the script this way
Quote:
test.ksh BUD01_AMD DLY
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  #2  
Old 08-09-2006
aigles's Avatar
Registered User
 

Join Date: Apr 2004
Location: Bordeaux, France
Posts: 1,212
Try with :
Code:
[ "$file" = "$fullpattern" ] || filecount=$filecount+1
or
Code:
[ "$file" = "$fullpattern" ] && break
filecount=$filecount+1
Jean-Pierre.
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