Here is my awk code in a shell script:

localRecDir=/somedirectory/
#
awk -v LRD="$localRecDir" '{out = sprintf ("%s0000000%s"),LRD,substr($3,4) ; print > out; close(out)}' *.log

Here is the contents of my *.log file I am trying to parse with my script:

000007 0110 07-0001583
000007 0110 07-0001584
000007 0110 07-0001585

I am expecting my script to:
1) get the 3rd field of my log file.
2) strip off the "07-" from the 3rd field
3) use sprintf to format a "pathname" to the "out" variable.
Essentially, I am trying to create 3 files:

/somedirectory/00000000001583
/somedirectory/00000000001584
/somedirectory/00000000001585

But I get this error:
awk: Syntax error
at line 1 of program << {out = sprintf ("%s0 ... >>
context is
{out = sprintf >>> ("%s0000000%s"), <<<
awk: illegal statement
at line 1 of program << {out = sprintf ("%s0 ... >>

Can someone please point out what I am doing incorrectly.

TIA
zoo591

you have mis-balanced ')'-s for your 'sprintf'

Thank you vgersh99. That was exactly the problem.
The script now works as intended.