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Old 08-07-2006
HLee1981 HLee1981 is offline
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Question Grepping for filenames containing value in specific segment within file
I am trying to grep for filenames containing a specific value within a particular segment. The lines containing the segment I'm looking through reads like "HL^1^^1^1", "10^9^9^0", and "HL^11^4^8^1". I would like to find the data that contains only the number nine after the third caret where the line begins with the phrase "HL". I've tried ranges with
Code:
grep -l ^HL\^[range]\^[range]\^9

, etc. but not every filename that should be returned are being reported. The values following the first and caret do not have a fixed range, nor is there a set number of how many characters will be contained there. Please help. Thanks!
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Old 08-08-2006
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Hitori Hitori is offline Forum Advisor  
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What if
$ grep -l ^HL\^[0-9]*\^[0-9]*\^9
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Old 08-08-2006
HLee1981 HLee1981 is offline
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Quote:
Originally Posted by Hitori
What if
$ grep -l ^HL\^[0-9]*\^[0-9]*\^9
Thank you! It works like a charm. Thanks again!
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Old 08-09-2006
HLee1981 HLee1981 is offline
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I would like to put together something that will use the mentioned criteria, and have a specific prefix be appended to the beginning of the filename if it contains the particular string of text I am looking for. I've several approaches in mind, but they are all manual, and I would like to get to the point where I can script this. Would someone be able to point me in the right direction to accomplish this please? Thanks.
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Old 08-10-2006
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Hitori Hitori is offline Forum Advisor  
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Code:
#!/bin/sh

grep -l ^HL\^[0-9]*\^[0-9]*\^9 * 2>/dev/null | while IFS= read vo
do
mv "$vo" prefix"$vo"
done

Note: cd first to the directory where the files were placed
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