![]() |
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| Shell Programming and Scripting Post questions about KSH, CSH, SH, BASH, PERL, PHP, SED, AWK and OTHER shell scripts and shell scripting languages here. |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| use variable for sed print line | atchleykl | UNIX for Dummies Questions & Answers | 3 | 02-23-2009 01:49 PM |
| How to print a value in the variable using awk ? | jisha | Shell Programming and Scripting | 1 | 01-14-2008 07:45 AM |
| print variable in file using awk | kamel.seg | Shell Programming and Scripting | 3 | 01-03-2008 06:43 AM |
| can awk print column using a variable ?? | jambesh | Shell Programming and Scripting | 36 | 09-26-2006 07:39 AM |
| print variable in awk | kazanoova2 | Shell Programming and Scripting | 8 | 05-17-2004 06:30 PM |
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
|
||||
|
How can I pass the name of the variable inside a for statment
I have a script something like below: classA=12 classB=14 classC=16 # classD = 20 all_class="classA classB classC" for i in $all_class do echo $i = $($i) #<---- this one not work #echo $i = $(echo $i) # <---- this one not work too #echo classA = $classA # <----- it can pass the classA = 12 done Also, how can i do if i don't know how many class will be there and i don't want to change the all_class value ? |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|