Hello,
I am having trouble extracting a specific line from a file when the line number is known. My first attempt involved grep -n 'hi' (the word 'hi will always be there) to get the line number before the line that I actually want (line 4).
Extra Notes:
-I am working in a bash script.
-The file size is always variable, so I couldn't use head or tail.
#file that I am evaluating

Use sed. Check the 'p' command in particular.

If you want a particular line number, say line 4, using head and tail commands:
Using sed:

You can use awk

awk 'NR==4{print $0}' filename

would print the 4th line for you.

Thank you everyone for responding. I went with the head to tail command. I previously didn't think the head/tail command would work but thank you for showing me the correct usage.

No need to explicitly print in the awk solution, it can simply be: awk 'NR==4' filename

head -4 | awk '{ print $1 }' < filename | tail -1