hello,
I want to grep the log file according to time and get the portion of log from one particular time to other.
I can grep for individual lines by time but how should I print lines continuously from given start time till end till given end time.

Appreciate your ideas,
Thanks
chandra

What does the time format look like ?

You might want to look at sed. Something on the lines of

Hello vino,
when I am using
sed -e "/start pattern/,/end pattern/p" file > tmpfile
tmpfile is containing duplicate lines from start pattern to end pattern along with the whole 'file'. I am not able to output only those lines ???
I was getting what I wanted when I do diff between two files but now I need it in a file.
Need assistance...Thanks

try sed -n not sed -e

thankyou, that helped.

If I have to put these lines from start pattern to end pattern into another file at the same place, I am not able to do so.
I tried to use sed -s again to try if it adds to the target file. but its adding at the end and also duplicating the lines.

sed -n 's/\"/echo config_start/,/echo \"end_install\"/p"//' config1.log>tmpfile

sed -n 's/\"/echo config_start/,/echo \"end_install\"/p"//' tmpfile config2.log
when I do this, it's adding each line in tmpfile twice and also at the end of config2.log

When looked into sed, i saw sed -f functionality but not able to get the syntax.

I need help in this one aswell.
Regards
chandra

I tried several combinations with awk, but the only piece missing is that the lines sitting at the right place in the file.
As sed -n picked the lines from a start pattern, I want to insert them exactly like that.
Any suggestions ...