Counting files in a directory that match a pattern - Page 4 - Shell Programming and Scripting

reborg · #22 07-20-2006

threads merged, please do not start multiple threads for the same topic.

dsravan · #23 07-20-2006

Reborg,

I am sorry for that!!! I got no answer so thought that new thread may incerase people viewing.

Anyway can you help me with this please?

reborg · #24 07-20-2006

Actually that exactly the reason that it is againts the rules of these forums.

However try this:

Code:

#!/bin/ksh
dir=/biddf/ab6498/dev/ctl
export dir
set -x 
myfilepattern=$@
integer filecount=0
for file in $myfilepattern_???_$(date +%Y%m%d) ; do
filecount=$filecount+1
done

if (( $filecount == 10 )); then
print "success"
exit 0
else
print "failure"
exit 1
fi

dsravan · #25 07-20-2006

Reborg,

I bow to you completely. You are great. It's working great man.

I will learn from this thread a lot. I will be active member from now on.

Once again thank you very much.

dsravan · #26 07-24-2006

Hi,

I have a problem with the script below. Basically it checks whether there is any file present with the name CARE01_DLY present for today's date in the directory /biddf/ab6498/dev/ctl and if the count =1 it says success otherwise error. But it doesn't seem to take the todays date file but checking if the file is present and saying success if the file is present with out checking for todays date. But i want the script to check for todays file only and if found it should through success otherwise error. The name of the file is sent as an argument to the script.

Quote:

#!/bin/ksh
dir=/biddf/ab6498/dev/ctl
export dir
set -x
myfilepattern=$@
integer filecount=0
for file in $myfilepattern_???_$(date +%Y%m%d) ; do
filecount=$filecount+1
done

if (( $filecount == 10 )); then
print "success"
exit 0
else
print "failure"
exit 1
fi

here is the output: The script is called like this script3.ksh BARE02_DLY

Quote:

+ dir=/biddf/ab6498/dev/ctl
+ export dir
+ set -x
+ myfilepattern=BARE02_DLY
+ typeset -i filecount=0
+ date +%Y%m%d
+ filecount=0+1
+ let 1 == 1
+ print success
success
+ exit 0

There is no file with this name for today but it's saying success.

Please help.

aigles · #27 07-24-2006

I found two problem in your script

$myfilepattern_???_$(date +%Y%m%d) is interpreted by the shell as ${myfilepattern_}???_$(date +%Y%m%d).
You must code like this : ${myfilepattern}_???_$(date +%Y%m%d)

The for statement returns the pattern itself if no file are found.
You must test for that pattern.

Code:

#!/bin/ksh
dir=/biddf/ab6498/dev/ctl
export dir
set -x 
myfilepattern=$@
fullpattern=${my_filepattern}_???_$(date +%Y%m%d)
integer filecount=0
for file in $fullpattern ; do
   [ "$file" != "$fullpattern"] && filecount=$filecount+1
done

if (( $filecount == 10 )); then
print "success"
exit 0
else
print "failure"
exit 1
fi

Jean-Pierre.

dsravan · #28 07-24-2006

Jean,

Thanks for the changes. But the script is still producing wrong result. There are 2 files with todays date in the directory and still it says failure. I think the main problem is pattern matching is is complaring like this:

CARE01_DLY_AUS_20060724 != CARE01_DLY_???_20060724 and saying no match. So please suggest.

Please see output:

Quote:

+ dev=/biddf/ab6498/dev/ctl
+ cd /biddf/ab6498/dev/ctl
+ echo /biddf/ab6498/dev/ctl
/biddf/ab6498/dev/ctl
+ myfilepattern=CARE01_DLY
+ + date +%Y%m%d
fullpattern=CARE01_DLY_???_20060724
+ typeset -i filecount=0
+ [ CARE01_DLY_AUS_20060724 != CARE01_DLY_???_20060724]
./script4.ksh[11]: test: ] missing
+ [ CARE01_DLY_MKT_20060724 != CARE01_DLY_???_20060724]
./script4.ksh[11]: test: ] missing
+ let 0 == 1
+ print failure
failure
+ exit 1

More UNIX and Linux Forum Topics You Might Find Helpful
Thread	Thread Starter	Forum	Replies	Last Post
Counting files in one directory	matrixtlm	UNIX for Dummies Questions & Answers	10	06-15-2007 04:14 PM
Counting number of files in a directory	iamalex	UNIX for Dummies Questions & Answers	2	09-05-2005 07:13 AM
List files that do not match the search pattern	olapxpert	UNIX for Dummies Questions & Answers	7	04-14-2005 12:49 PM
List files that do not match the search pattern	olapxpert	IP Networking	1	04-14-2005 11:37 AM
rm files in a directory, looping, counting, then exit	JporterFDX	Shell Programming and Scripting	6	07-18-2002 05:56 AM

Thread Tools	Search this Thread
Show Printable Version Email this Page	Search this Thread: Advanced Search
Display Modes
Linear Mode Switch to Hybrid Mode Switch to Threaded Mode