Hi All,

I need help in writing a script. I need a script that takes a name as a parameter and executes the follwoing steps.

The name will be like BUDGET01_BARE_DLY_YYYYMMDD, BUDGET02_BARE_DLY_YYYYMMDD etc. The YYYYMMDD represent today( systemdate). This names have to be passed as paramaters to the script and what it has to do is:

1. count the number of files for that name in the direcotry /opt/app ; for e.g for the file name BUDGET01_BARE_DLY_YYYYMMDD there will be 27 files with that name. if the number is less than 27 for BUDGET01_BARE_DLY_YYYYMMDD then through an error saying that not enough files for today. Then this has to happen to BUDGET02_BARE_DLY_YYYYMMDD similarly. If it has enough files then remove the last BARE_DLY_YYYYMMDD characters in the names. This has to occur recursively for different file names.

Any help will be greatly appreciated.

I think you are a bit confused. For any given day, you can have only one file with the name BUDGET01_BARE_DLY_YYYYMMDD. For instance, for today 20 July 2006, the filename will be BUDGET01_BARE_DLY_20060720.

Do you mean that you will have filenames such as BUDGET01_BARE_DLY_YYYYMMDD, BUDGET02_BARE_DLY_YYYYMMDD, etc... upto BUDGET27_BARE_DLY_YYYYMMDD?

I am sorry I was not clear in my post. When i said i will have 27 files with that name for that day means the file name will be like below. The MKT represents 27 cities and hence I will have 27 files per day. For e.g if AUStralia is the market i have BUDGET01_TLG_DLY_<AUS>_<YYYYMMDD>.dat. For India i have BUDGET01_TLG_DLY_<IND>_<YYYYMMDD>.dat. There will be 27 files from different countries. I think I am clear in what I want now. I need to pass BUDGET01_yyyymmdd as parameter and continue to check if there are 27 files with that name otherwise I have to thruogh an error. This has to be done for BUDGET2 files also. Please help.