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07-19-2006
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Search for \n
Hi All,
How can i searc for a \n in a file. Not a newline but \n itself. In detail i have a statement printf("\n hello"); here i need to find \n. Can u please help on this.. Thanks in advance Regards, Chanakya |
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07-19-2006
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A sed solution Code:
sed -n -e '/\\n/p' in.txt A grep solution is Code:
grep -E '\\n' in.txt To get a single \ you need to escape it. Last edited by vino; 07-19-2006 at 03:03 AM.. Reason: simpler solution... |
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07-19-2006
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Vino,
Thank a lot.. i got what i want. Can u explain me the command - Chanakya |
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07-19-2006
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Quote:
Code:
sed -n -e '/\\n/p' in.txt -n means do not print the lines that are read. -e script to be executed. '/\\n/p' For all lines that match the pattern containing \n, print it. We need the flag p to go with the -n option. in.txt input file Code:
grep -E '\\n' in.txt -E consider the following expression as an extended regular expression. In fact -E is not needed at all. You can drop it. |
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07-19-2006
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Thats fine.. I just tried the same in vi editor (s/\\n/g), could not find.. can u help me in this aspect
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07-19-2006
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What are you trying to do ? Use the vi editor or an external tool ?
If it is the external tool, use the solutions I gave you. If it is vi, then /\\n will show you all the occurences. |
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