Hi everybody:
I'm trying to create files database, and to do this I'd like to create them with this format:

date hour julian-day SZA other-values

from the original file I've this format:

- , year, julian-day, minute, other-values
112,2004,84,2300,-3.352,,,,,,,,,,,

To do this I'd created this awk-script:
#
# here there are different format staments
#

# gregorian date conversion
{
if($3 <= 31) dg = $3; mm=01; # january
if($3 > 31 && $3 <=59) dg = $3-31; mm = 02; # february
if($3 > 59 && $3 <=90) dg = $3-59; mm = 03; # march
if($3 > 90 && $3 <=120) dg = $3-90; mm = 04; # april
if($3 > 120 && $3 <=151) dg = $3-120; mm = 05; # may
if($3 > 151 && $3 <=181) dg = $3-151; mm = 06; # juny
if($3 > 181 && $3 <=212) dg = $3-181; mm = 07; # july
if($3 > 212 && $3 <=243) dg = $3-212; mm = 08; # august
if($3 > 243 && $3 <=273) dg = $3-243; mm = 09; # september
if($3 > 273 && $3 <=304) dg = $3-273; mm = 10; # octuber
if($3 > 304 && $3 <=334) dg = $3-304; mm = 11; # november
if($3 > 334 && $3 <=365) dg = $3-334; mm = 12; # december
};

# hour format

{
if ($4 <=9 ) $4 = 000$4;
if ($4 >=10 && $4 <=59 ) $4 = 00$4;
if ($4 >=100 && $4 <=959 )$4 = 0$4;
};

and the output I'd like this:

# print final file with format
{
printf format, $2 mm dg, $4, $3, SZA, $5, $6, $7, $8, $9, $10, $11, $12, $13
}' abr01_04.mpy > abr01_04.csv

and I've this:

20041226 00 85 136.11934 -2.595 -2.697 .044 25.31 -1.19 5.334 1.058 .197 .096
20041226 01 85 136.11934 -2.766 -2.588 .044 25.42 -1.19 5.382 .753 .205 .193
20041226 02 85 136.11934 -2.984 -2.429 .044 25.37 -1.189 5.405 .896 .197 .116
20041226 03 85 136.11934 -2.98 -2.419 .044 25.31 -1.189 5.41 .789 .183 .125
20041226 04 85 136.11934 -3.005 -2.344 .044 25.42 -1.193 5.418 .914 .234 .141

First I don't know why the format date the month doesn't appear correctly, in this case it must be 05-april cause julian day is 85, and in the other hand the hour format doesn't appear as I'd like, because in this case it is 00 where it must be 0000.
Could anybody tell me how solve it?.
Thanks in advance.