Previous day's date in Perl?

rajus19 · #1 (**permalink**) 07-12-2006

Hi All,

I want to find the previous day's date and store that in a variable, which will be usuful for further processing.

Any help please.

Regards,
raju

blowtorch · #2 (**permalink**) 07-13-2006

This is exactly what you want:

Code:

a=$(perl -w -e '@mytime=localtime (time - $ARGV[0]); printf "%d%.2d%.2d", $mytime[5]+1900,$mytime[4]+1,$mytime[3];' 86400)
echo $a

You could have also gotten help from the perl man pages. Check perlfunc in particular.

rajus19 · #3 (**permalink**) 07-14-2006

Thanks Blowtorch.

As a unix command its working fine, I tried to put in my perl program and made the changes to assign the previous date(format mm/dd/yyyy) to a variable but its not working fine.

Could you please look at once.

thanks,
raju

blowtorch · #4 (**permalink**) 07-15-2006

The command I gave will give the output in the yyyy/mm/dd format. You will have to switch the mytime[x] around to get the output in the format that you want.

And another thing, are you using that snippet in a perl program? Then you can use this:

Code:

@mytime=localtime (time - 86400); 
#from this point on, you can use $mytime[3] for day, $mytime[4] for month (zero based) and $mytime[5] for the year (add 1900)

rajus19 · #5 (**permalink**) 07-18-2006

Thanks blowtorch

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