Hi,

I have a dat file havinf the data like this.

it contains 3 fields like this.

for ex :

*** *** ***
*** *** ***
*** *** ***
12.34 45.64 78.21
*** **** ****

Now i want to write rows only which has data.
awk will work.
please provide syntax for this.

grep -v "*" ?

not working

pls post what u have tried to do for this!

Close. Drop the double quotes.

grep -v '*'

This should work

cat <filename> | awk '$0!~/\*/{print}' > desired_file


All its doing is matching if '*' exists within a line. If it doesn't it prints the line. You can redirect the output to a file to get the desired lines.