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Old 06-27-2006
sprellari sprellari is offline
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Posts: 49
Awk problem

Hi. I'm really not good in awk syntax or scripting by awk and therefore requesting some assistance.



Code:
cat $TEMPFILE | grep -v ^$ | awk '{print $2, $3, $4, $8}' | while read appname apphandle eitthvad pid
do
        cat $OUTFILE | awk -F ";" '$1 == '$pid' {print $1, $2, $3, $4, $5, $6, $7, $8, '$apphandle $appname'};'
done

Awk complains about the "'$apphandle $appname'" part. I can include one variable in the output statement by using ' around the variable name, but when there are two or more things break down. Any thougts?
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Old 06-27-2006
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reborg reborg is offline Forum Staff  
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put double quotes inside the single quotes (before and after the bit that causes problems). By that way, that is a really ugly way to write code, with several UUOCs, and a UUOG.
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Old 06-27-2006
tmarikle tmarikle is offline Forum Advisor  
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Here is one way to do it. I would avoid passing in variables in the manner that you are attempting. It's too messy.


Code:
while read appname apphandle eitthvad pid
do
    [[ ${appname}${apphandle}${eitthvad}${pid} = "" ]] && continue
    nawk -F\; -v pid=${pid} -v apphandle=${apphandle} -v appname=${appname} '
        $1 == pid {
           print $1, $2, $3, $4, $5, $6, $7, $8, apphandle appname
        }' $OUTFILE
done < $TEMPFILE

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