AWK question?

J_ang · #1 (**permalink**) 06-22-2006

I have question about awk if someone can help me here. I want to find a string (file has just one row) and then get the position of the column.

let say i have 4 columns

a b c d

Look for b and somehow get the column position in this case b is at $2 script doesn't know what is the position of the column. So if awk or something else can help me to get position of the column.

Thanks in Advance.

Doc_RuNNeR · #2 (**permalink**) 06-22-2006

It is necesary to do it with awk?

Because a script can do it

.........
cont=0
for i in `cat (the file)`
do
if [ `echo $i` = (the name you would like to find) ]
then
break;
else
(( cont = cont + 1 ))
done
echo "the position is -$cont-"
.........

Bye

futurelet · #3 (**permalink**) 06-22-2006

Code:

ruby -e 'p gets.split.index("bar").succ' myfile

Code:

newlisp -e '(+ 1(find "foo" (parse (read-line))))' <myfile

Klashxx · #4 (**permalink**) 06-23-2006

In awk:

Code:

$ cat file 
a b c d
e c g h
a b j c
$ awk -v var=c '{for (i=0;i<=NF;i++){if(var == $i){ print "Var "var" found in column "i" line "NR }}}' file
Var c found in column 3 line 1
Var c found in column 2 line 2
Var c found in column 4 line 3

Ygor · #5 (**permalink**) 06-23-2006

Try...

Code:

echo 'a b c d' | awk 'BEGIN{RS=FS}/b/{print NR}'

J_ang · #6 (**permalink**) 06-23-2006

Thanks for everybody's input couldn't accomplish my mission yet

Output of $* (a b c d)

typeset -u P=`echo $*|awk 'BEGIN{RS=FS}/b/{print "$"NR}'`

Rather then giving me b it gives me $2.

Thanks in advance.

J_ang · #7 (**permalink**) 06-23-2006

Let me explain little bit what i am trying to accomplish i want to find a string in arugments that have been passed to script then get the column number and based on column number get the value of that arugment.

Thanks

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