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#1
05-25-2006
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Bash Secure Shell Script
im trying to create a little script that does a secure shell login based on some input(ip address, server name, etc...)
everything in perenthesis() as been edited for privacy reasons I cant figure out what im doing wrong? if you can post some info for me that would be awsome ------------------------The Script------------------------------ #!/bin/bash port="22" echo 'What server:?(server1, server2 or type ip address)' read $server if [ $server = "(server1)" ]; then ssh (uname)@(ipaddress) -p(port number) elif [ $server = "(server2)" ]; then ssh (uname)@(ipaddress) elif [ "$server" -eq *.*.*.* ]; then echo 'User:?' read $user echo 'port:?' ssh $user@$server -p$port else exit fi Last edited by jzocco; 05-25-2006 at 12:23 PM. 
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#2
05-25-2006
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I don't understand - do you have a problem with the script above? Either way, it looks like you're being a bit redundant - instead of them typing in the server name, then you check if they typed in the server name, then you execute ssh with the server name, why not accept their input:
Code:
#! /bin/bash
echo -n "Enter a server name or IP address: "; read _srv
echo -n "Enter username for $_srv, or enter for \"${LOGNAME}\": "; read _usr
[[ -n $_usr ]] && _usr=${_usr}@
echo ssh ${_usr}${_srv} || {
echo "SSH encountered an error! " >&2
exit 1
}
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