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  #1  
Old 05-11-2006
Klashxx's Avatar
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awk:Problem with getline
Code:
$ echo |awk ' BEGIN {"date" | getline current_time;close("date");print "Report printed on " current_time}'                                                               
Report printed on Thu May 11 14:57:29 METDST 2006
This example works fine but how can i print all the output when is longer than 1 line??

Thx in advance.
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  #2  
Old 05-11-2006
vgersh99's Avatar
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Quote:
Originally Posted by Klashxx
Code:
$ echo |awk ' BEGIN {"date" | getline current_time;close("date");print "Report printed on " current_time}'                                                               
Report printed on Thu May 11 14:57:29 METDST 2006
This example works fine but how can i print all the output when is longer than 1 line??

Thx in advance.
pls elaborate of what you're looking for - it's a bit vague. An example could be helpful.
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  #3  
Old 05-11-2006
Klashxx's Avatar
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Of course , i want to execute a system function (output longer than 1 line) and capture all the results.

This "bad" ex shows 1 line only:
Code:
$ awk ' BEGIN {"who" | getline USERS;close("who");print USERS}'
jefe       pts/1        May 12 07:04
Apparently the 'while ( (getline < "data") > 0 )' structure only handles files.

Thanks.
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  #4  
Old 05-12-2006
Klashxx's Avatar
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Join Date: Feb 2006
Location: Almerķa, Spain
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Ok , issue solved !

This piece did the job:
Code:
awk ' BEGIN { while (("who" | getline) > 0){print};close("who")}'
Cheers
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