Hi all,

how to find a character position in a word/line

Eg.

Unix forum is the best site.

Now in above line i want to find the character 'x' position
i.e 4

As in oracle we can make use of 'instr' function to do this.
Is their any thing in Unix shell script ?

Thanks In advance.

my way of doing it:

$ echo "Unix forum is the best site." | grep -o "[-_a-zA-Z0-9\.]" | grep -n x

Thanks

but it give output as 4:x

I nt it to be 4

$ echo "Unix forum is the best site." | grep -o "[-_a-zA-Z0-9\.]" | grep -n x | cut -d: -f1

Thanks a lot

Or use the expr command with 'index' :

To return the first position of where any characters in the string "de" is found in "abcdef", enter:

expr index abcdef de

The following is displayed:
4

cheers