using regular expressions in c shell control structure - Shell Programming and Scripting

ballazrus · #1 (**permalink**) 02-18-2006

i cant get around using regular expressions in if/else statements. it simply doesnt give me the right results.

i've tried using switch/case but that is just as sh!tty as well. (pardon my french but im getting frustrated with c shell..only reason why im writing in it is because it's a hwk assignment to compare bourne with c shell)

anyways
im trying to write a regular expression that says a string must begin with A have any number of [d-f] in between and end with B

so what i got is basically this..

=========

echo -n "Enter a string: "

set $string = $<

if ($string =~ '^A[d-f]*B$') then
echo "accepted"
else
echo "rejected"
endif

exit
==========

it simply doesnt work

cshell doesnt seem to like the anchors or other special characters.

any feedback would be greatly appreciated.

RTM · #2 (**permalink**) 02-19-2006

Please read the Rules about homework assignments. Thanks.

ballazrus · #3 (**permalink**) 02-19-2006

sorry. however, that piece of code is just 5% of my assignment as a whole. and i'm not posting my assignment and asking somebody to do it for me, i have something and i'm asking for advise on how to get it to work. i cant see how most ppl in here arent asking questions related to their assignments.

vgersh99 · #4 (**permalink**) 02-19-2006

Quote:

Originally Posted by ballazrus

sorry. however, that piece of code is just 5% of my assignment as a whole. and i'm not posting my assignment and asking somebody to do it for me, i have something and i'm asking for advise on how to get it to work. i cant see how most ppl in here arent asking questions related to their assignments.

....'cause the rules are eing enforced?
I don't know......

here's something to start with.......

Code:

#!/bin/ksh

a='AdeffedB'

if [[ $(expr  "$a" :  '^A[d-f][d-f]*B$') -ne 0 ]]; then
   echo 'found'
else
   echo 'NOT found'
fi

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