Single character wildcard for SED

stevefox · #1 (**permalink**) 02-15-2006

Could someone tell me the single character wildcard for SED?

I have the file below:

Code:

$ more input2
AAA /A/B/C BBB /D/E/F
CCC /G/H/I DDD

I want to remove all strings which contain forward slashs "/" to get the below:

AAA BBB
CCC

I tried to do it in SED by the command below but I couldn't find out the single character wildcard and failed.

$ sed "s/\/.*\/?//g" input3

If there's an awk solution to the above please tell me as well.

Any help will be appreciated.

vino · #2 (**permalink**) 02-15-2006

Code:

 sed -e 's#/.##g' input.txt

stevefox · #3 (**permalink**) 02-15-2006

Thank you vino for your quick response!
By the way is there a manual/reference for the use of 's#/.##g' command?

vino · #4 (**permalink**) 02-15-2006

Quote:

Originally Posted by stevefox

Thank you vino for your quick response!
By the way is there a manual/reference for the use of 's#/.##g' command?

Yups. See man sed.

If you are talking about the #, then see info sed. If you dont have info sed, this is what it says

Code:

The `s' Command
===============

   The syntax of the `s' (as in substitute) command is
`s/REGEXP/REPLACEMENT/FLAGS'.  The `/' characters may be uniformly
replaced by any other single character within any given `s' command.
The `/' character (or whatever other character is used in its stead)
can appear in the REGEXP or REPLACEMENT only if it is preceded by a `\'
character.

stevefox · #5 (**permalink**) 02-15-2006

Thanks vino.
I understood how the command worked.
But it only works for removing strings with a fixed number of characters after the forward slash.

If I had an input with unfixed number of characters after the forward slash like below:

Code:

$ more input2
AAA /aaa/B/C BBB /D/E/ff
CCC /D/eeee/F DDD

How can I remove all strings which contain forward slashs "/" to get the below:

AAA BBB
CCC DDD

matrixmadhan · #6 (**permalink**) 02-15-2006

Code:

awk '
{ 
for (i=1; i<= NF; i++ ) 
{
if ( $i !~ /\// ) 
	{ 
	printf $i" "
	} 
}
printf "\n"
}' file

vino · #7 (**permalink**) 02-15-2006

Code:

sed -e 's#/[^/ ]*##g'

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