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02-01-2006
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Inputs from a file
Hi,
I have a shell script that has to taken inputs from a file say "Inputs". Now I take 2 inputs at a time. Suppose the Inputs file contains numbers like 2 3 4 5 Now I have a written a script for adding 2 numbers. When I run the script for first time 2 and 3 must be the inputs. When i run the script for the second time the inputs should be 4 and 5. Is there is any way to do this. I know that the inputs can be taken using 'exec'. But , how can i do for this case. Thanx in advance 
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02-01-2006
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cat filename | paste - - | while read a b
do vl=$(( a + b )) echo $vl done if you are very particular to include your script to add the numbers, remove the line vl=$(( a + b )) and add your script name with variable a and b.
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02-01-2006
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this is a round-abt way, better dont use it i thought of giving it a try thats it
Code:
# !/usr/bin/ksh
#1
#The above line indicates the run
num=`sed 2q $0 | tail -1 | sed 's/#//'`
cnt=1
counter=0
sum=0
while read line
do
if [ $cnt -eq $num ]
then
if [ $counter -le 1 ]
then
sum=$(($sum + $line))
counter=$(($counter + 1))
else
break
fi
else
cnt=$(($cnt + 1))
fi
done < data
echo "sum is $sum"
cnt=$(($cnt + 2))
sed 1q $0 > tmp
echo "#$cnt" >> tmp
awk 'NR>2' $0 >> tmp
mv tmp $0
chmod 744 $0
exit 0
Code:
>cat data 2 3 4 5 6 7 8 9 Code:
>sum.ksh sum is 5 >sum.ksh sum is 9 >sum.ksh sum is 13
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02-01-2006
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Doing away with the cat and the paste, this will work
Code:
#! /bin/ksh
echo "2
3
4
5" | while read line
do
NUM1=$line
read line
NUM2=$line
SUM=$((NUM1+NUM2))
echo $SUM
done
Code:
#! /bin/ksh
while read line
do
NUM1=$line
read line
NUM2=$line
SUM=$((NUM1+NUM2))
echo $SUM
done < input.file
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