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#1
01-29-2006
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grep "$1\.mylogs\.20" ?
Can any kind souls explain the above to me please?
In additional, the following line (within brackets) also muffles me, please enlighten me. ( awk '{print $2}' ) 
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#2
01-29-2006
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grep "$1\.mylogs\.20"
Usually $1 is the first parameter passed to a shell script. Say, $1 is new2ss in this case. So the search string is "new2ss.mylogs.20" The \ is used to escape the character which appears just after the \ In the unix world, a . represents any character. So a /. would mean a . in its entirety. Your grep search pattern can be like this as well grep "$1.mylogs.20"
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#4
01-30-2006
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Code:
[~]$ echo "Welcome to the unix forums" | awk '{ print $2 }'
to
For more info read the man pages of awk. Last edited by vino; 01-30-2006 at 08:15 AM.
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#6
07-04-2007
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new2ss, please get some basic understanding about regular expression syntex. so that u wont get any problem in future.
these are not so difficult.
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