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#8
12-16-2005
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Hi all,
Thank you very much for your prompt responses. I got some solution in the net its working fine in my desktop(windows 2000) with cygwin, but its giving bailing error in my server(Sun OS 5.8). Could any one of you help me to solve the problem, the code is below. #!/bin/ksh dte='2003-06-11' eval $(echo "${dte}" | awk -F- '{printf("year=%s month=%s day=%s\n", $1, $2, $3)}') echo "year->[${year}] month->[${month}] day->[${day}]" cal "${month}" "${year}" | awk -v day="${day}" ' FNR > 2 { for(i=1; i <= NF; i++) if ( $i == day) { #printf("day->[%d] row->[%d]\n", $i, FNR-2) printf("%d\n", (NF == 7 || FNR!=3) ? i-1 : i+(6-NF)) exit } } ' Thanks in Advance Rinku 
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#10
12-18-2005
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it works sir...
Quote:
thanks Perderabo....datecalc is the real answer to all date manipulations....
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#11
4 Weeks Ago
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I wonder : Is there a way in a KSH shell what the yesterdays last business day is:
so for instance monday 03112008 (ddmmyyyy) should be give 31102008. I've search this site but couldn't found something. Did also tried with Julians Day I'm using AIX 5.2.0 with KSH shell pls give me a hand
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#12
4 Weeks Ago
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Code:
$ cat yesterbusinessday
#! /usr/bin/ksh
alias datecalc=./datecalc
echo "Enter year month day"
read year month day
if (($(datecalc -d $year $month $day) == 1)) ; then
offset=3
else
offset=1
fi
datecalc -j $(($(datecalc -j $year $month $day) - offset))
exit 0
$ ./yesterbusinessday
Enter year month day
2008 11 3
2008 10 31
$ ./yesterbusinessday
Enter year month day
2008 10 31
2008 10 30
$
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#13
4 Weeks Ago
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thx Perderabo for the fast reply ,
but i got a problem with the # ./yesterbusinessday + alias datecalc=./datecalc + echo Enter year month day Enter year month day + read year month day 2008 11 3 + ./datecalc -d 2008 11 3 ./yesterbusinessday[7]: ./datecalc: not found. + (( == 1 )) ./yesterbusinessday[7]: == 1: 0403-057 Syntax error  Sorry i'm new
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