Is there a command in unix to find the union of two files and removing the union from one of the files?


e.g. I have two files input1.txt and input2.txt with the contents below:

$ more input1.txt
4
2
3
2

$ more input2.txt
5
4
4
8
2

ruby -e 'puts IO.read($*[0]).to_a - IO.read($*[1]).to_a' dat1 dat2

Thanks futurelet.
Is there a way to do this without using ruby and only using standard HP Unix commands?

awk '{print $0}' input1.txt input2.txt |sort -u

Thanks Livio
However your code did not give input1.txt minus the union of input1.txt and input2.txt which is 3.

I worked out that I can do this by the code below but is there a simpler way to do this using standard Unix commands? (possibly in one line?)

cat input1.txt input2.txt | sort | uniq -d > union
cat input1.txt union | sort | uniq -c > union2
sed -n '/1 /p' union2 > union3
sed -e 's/   1 //g' union3

I found out that it can be done by

sort -u input1.txt > temp1.txt
sort -u input2.txt > temp2.txt
comm -23 temp1.txt temp2.txt