Escape character in vi?

stevefox · #1 (**permalink**) 11-16-2005

I want to replace a string which contains "/" in vi but what is the escape character for forward slash?

e.g. I have a text file with the contents below and I want to replace "/Top/Sub/Sub1" with "ABC".

/Top/Sub/Sub1

The replace command I am using is %s/string_before_replace/string_after_replace/g.

zazzybob · #2 (**permalink**) 11-16-2005

%s/\/Top\/Sub\/Sub1/ABC/g

Cheers
ZB

stevefox · #3 (**permalink**) 11-16-2005

Thanks zazzybob!

mschwage · #4 (**permalink**) 11-16-2005

Make life easy for yourself. The "/" in the search/replace command is just a default. How about this:

%s#/Top/Sub/Sub1#ABC#g
or
%s+/Top/Sub/Sub1+ABC+g
or
%s_/Top/Sub/Sub1_ABC_g

...etc... You get the idea. If you know you've got a lot of /'s, try to avoid all those \/'s. It's ugly and error-prone.
-mschwage

Neo · #5 (**permalink**) 11-17-2005

Great idea. I like the mschwage's suggestion. I used to use the \/ method, but now I will change to mschwage's default-changing method :-)

Thanks for the contribution. I love it when I learn something new here on UNIX.COM!

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