check space !!! - Shell Programming and Scripting

kamlesh_p · #1 11-09-2005

The have written the below script :-
============================

SPACE=`bdf /DATA_TRANSFER|awk '{print $4}' |grep "%"`
TEST="96%"
if [ "$SPACE" < "$TEST" ]
then
echo "Continue ....."
sleep 2
else
echo " Current space for DATA_TRANSFER is less than 02 %"
echo " Pls clear space and than continue ....."
sleep 3
exit 1
fi

but after execution it give's following error:-
================================
+ ./checkspace[4]: 96%: cannot open
I am running the same on HP-UX 11.11 version and in ksh shell.
Can you assist in resolving the same ?

vgersh99 · #2 11-09-2005

not tested........

Code:

#!/bin/ksh

typeset -i SPACE=$(nawk '/%/{print substr($4, 1, length($4)-1)}' bdf/DATA_TRANSFER)
typeset -i TEST="96"
if (( $SPACE < $TEST ))
then
........

Perderabo · #3 11-09-2005

You can't do stuff like:
if [ "$SPACE" < "$TEST" ]
At least not sensibly. " < $TEST" is used to redirect the input of the test command to the file called $TEST. Since test does not use an input file, this does nothing. This is one of several dozen reason why you should switch to:
if [[ whatever ]]
Not only would < do what you wanted it to, but then you no longer need the quotes around the variables.

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