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#1
02-20-2013
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Create a flat file and directory structure
Hi All, is there any work around to generate the file and directory structure like below at left side at Output? and exclude all file except .abc .txt Current Directory structure Code:
|-------------files |---------------Share |-----------------dir1 |-----------------dir2 |-----------------dir3 |-----------------dir4 |-----------------dir5 |-----------------dir6 |-----------------dir7 |-----------------dir8 |-------------------IMG |---------------------IMG001 |---------------------IMG002 |-----------------------1234.abc |-----------------------abcd.txt |-------------------00001 |---------------------IMG |-----------------------IMG1 |-----------------------IMG2 |-------------------Sample |---------------------hello |-----------------------prod |-------------------------NAD |---------------------------NAT |-------------------------TEXT |---------------------------TEXTILE1 |---------------------00002 |-----------------------IMAG |-------------------------IMAG1 |-------------------------IMAG2 |-----------------dir9 |-----------------dir10 |-----------------dir11 print Output file look like this Code:
1 files 1.1 Share 1.1.1 dir1 1.1.2 dir2 1.1.3 dir3 1.1.4 dir4 1.1.5 dir5 1.1.6 dir6 1.1.7 dir7 1.1.8 dir8 1.1.8.1 IMG 1.1.8.1.1 IMG001 1.1.8.1.2 IMG002 1.1.8.1.2.1 1234.abc 1.1.8.1.2.2 abcd.txt 1.1.8.2 00001 1.1.8.2.1 IMG 1.1.8.2.1.1 IMG1 1.1.8.2.1.2 IMG2 1.1.8.3 Sample 1.1.8.3.1 hello 1.1.8.3.1.1 prod 1.1.8.3.1.1.1 NAD 1.1.8.3.1.1.1.1 NAT 1.1.8.3.1.1.1.2 TEXT 1.1.8.3.1.1.2.2.1 TEXTILE1 1.1.8.3.2 00002 1.1.8.3.2.1 IMAG 1.1.8.3.2.1.1 IMAG1 1.1.8.3.2.1.2 IMAG2 1.1.9 dir9 1.1.10 dir10 1.1.11 dir11 Thank you Last edited by heros; 02-20-2013 at 09:08 PM.. |
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#2
02-20-2013
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Is this a one-time or re-occuring task? If is just a one time job, it is easier to just create the directories manually than writing a script for parsing this input file.
The -p switch of mkdir might come handy when creating the directories. |
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#3
02-20-2013
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My apologies, I mean File and Directory Structure is my current structure directory, but i want to generate a full path of file and directory structure and print to a file, not to create a directory
thanks for response ---------- Post updated 02-21-13 at 10:19 AM ---------- Previous update was 02-20-13 at 06:43 PM ---------- is this possible for unix? |
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#4
02-20-2013
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This comes close, only issue is unix sorts alphabetically so order is dir1 dir11 dir12 dir2 Code:
find ./files \( -type d -o -name "*.abc" -o -name "*.txt" \) -print | awk '
function ppath(p, f, c) {
s=index(f, "/");
if (!p) return ppath(substr(f,1,s-1), substr(f,s+1), "");
if (!s) pf=p"/"f;
else pf=p"/"substr(f,1,s-1);
if (!(pf in found)) {
found[p]++;
found[pf]=0
}
if (!s) return (c?c".":"") found[p] " " f
return ppath(pf, substr(f, s+1), (c?c".":"") found[p])
}
{ print ppath("", $0, "") }output: Code:
1 files 1.1 Share 1.1.1 dir1 1.1.2 dir10 1.1.3 dir11 1.1.4 dir2 1.1.5 dir3 1.1.6 dir4 1.1.7 dir5 1.1.8 dir6 1.1.9 dir7 1.1.10 dir8 1.1.10.1 00001 1.1.10.1.1 IMG 1.1.10.1.1.1 IMG1 1.1.10.1.1.2 IMG2 1.1.10.2 IMG 1.1.10.2.1 IMG001 1.1.10.2.2 IMG002 1.1.10.2.2.1 1234.abc 1.1.10.2.2.2 abcd.txt 1.1.10.3 Sample 1.1.10.3.1 00002 1.1.10.3.1.1 IMAG 1.1.10.3.1.1.1 IMAG1 1.1.10.3.1.1.2 IMAG2 1.1.10.3.2 hello 1.1.10.3.2.1 prod 1.1.10.3.2.1.1 NAD 1.1.10.3.2.1.1.1 NAT 1.1.10.3.2.1.2 TEXT 1.1.10.3.2.1.2.1 TEXTILE1 1.1.11 dir9 ---------- Post updated at 02:49 PM ---------- Previous update was at 01:49 PM ---------- Another solution without recursion: Code:
find ./files \( -type d -o -name "*.abc" -o -name "*.txt" \) -print | awk '{
c=split($0,v,"/");
f=v[1];
for(i=2;i<=c;i++) {
if(!(f in P)) P[f]=0;
if(!(f"/"v[i] in P)) P[f]++;
P[f"/"v[i]];
printf "%s",P[f] (i<c?".":"")
f=f"/"v[i]
}
print " " v[i-1];
}'Last edited by Chubler_XL; 02-20-2013 at 11:50 PM.. Reason: Optimised |
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#5
02-21-2013
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very appreciate the scripts, sir could you please explain a little bit more whats going on of your script?
thank again. |
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#6
02-21-2013
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The find statement produces a list of files and directories that match the criteria (directory or name ends in .txt or .abc) something like this: Code:
./files ./files/Share ./files/Share/dir1 ./files/Share/dir10 ...etc Each directory component is broken out and put into a array (found[] in first script and v[] in second) Each element in the array counts how many children sit below it Code:
v[.]=1 v[./files]=1 v[./files/Share]=11 v[./files/Share/dir8]=3 ... Now if a new directory or file ./files/Share/dirX is processed the count in v[./files/Share] will be incremented to 12 because no entry exists for v[./files/Share/dirX] this allows the output of 1.12.1 dirX to be printed. |
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#7
02-21-2013
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Thank so much for your help sir. ---------- Post updated 02-22-13 at 09:11 AM ---------- Previous update was 02-21-13 at 02:15 PM ---------- Sir have a question, what about exclude some folder and their succeeding sub directory, I tried to add something like this: Code:
\( -type d -o -name "*.dat" -o -name "*.txt" -o ! -name "warcraft" \) is not working, is there any work around? need to exclude directory and their succeeding subdirectory. Thanks Last edited by heros; 02-22-2013 at 12:47 AM.. |
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