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#1
01-21-2013
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Comparison of two variables with IF loop
Hello, My script is like : Code:
#!/bin/sh -x
TODAY=$(echo `date +"%b%d"`)
FILE_DATE=$(ls -l test.sh | awk '{print $6$7}')
echo "file date=$FILE_DATE"
echo "date=$TODAY"
if ["$TODAY" == "$FILE_DATE"]];then
echo "file is correct"
else
echo "file is incorrect"
fiand The Output is : Code:
$ ./test.sh
+ + date +%b%d
+ echo Jan21
TODAY=Jan21
+ + ls -l test.sh
+ awk {print $6$7}
FILE_DATE=Jan21
+ echo file date=Jan21
file date=Jan21
+ echo date=Jan21
date=Jan21
+ [Jan21 == Jan21]]
./test.sh[6]: [Jan21: not found
+ echo file is incorrect
file is incorrectPlease let me know where i am doing wrong. Regards, saurau |
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#2
01-21-2013
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Your if statement has one opening [ and two closing ]]. You also need a space after [ and before ]. There's also an unnecessary use of echo and backticks: Code:
TODAY=$(echo `date +"%b%d"`) Could be: Code:
TODAY=$(date +"%b%d") |
| The Following User Says Thank You to Scott For This Useful Post: | ||
saurau (01-21-2013) | ||
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#4
01-21-2013
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Quote:
 |
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