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#1
01-17-2013
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Print lines that match regex on xth string
Hello, I need an awk command to print only the lines that match regex on xth field from file. For example if I use this command Code:
awk -F"|" ' $22 == "20130117090000.*" ' It wont work, I think, because single quotes wont allow the usage of the metacharacter star * . On the other hand I dont know what other syntax should I use to avoid the usage of the single quotes. |
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#2
01-17-2013
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Code:
awk -F"|" '$22 ~ /20130117090000/' ... |
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#3
01-17-2013
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Quote:
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