Hi,
I am new to Unix/ksh script and will like to check how do I retrieve just the count of '258' in the last line in a text file ?
There will be this "TRL" appended with number of count at the last line in a text file .

TRL0000000258

var=`grep 'TRL' $HOME/folder/test.txt | wc -l`

Can you post the input file?

---------- Post updated at 05:54 AM ---------- Previous update was at 05:38 AM ----------

I think you are excepting this one...

 echo "TRL44440000000258"|awk '{ print substr( $1, length($1) - 9, length($1) ) }'

Try:

var=$(tail -1 infile)
var=${var#TRL}

var=$(sed -n '$s/TRL//p' infile)

Input file :

AAAAAAAAAAAAAAAA
BBBBBBBBBBBBBBBB
CCCCCCCCCCCCCCCC
TRL0000000258

awk ' /^TRL/ {sub(/TRL/, "") ; print } ' file

0000000258

awk '/^TRL/{sub(/TRL0+/,"")}1' test.txt

Yet another way...

echo TRL0000000258 | awk '{gsub("[^0-9]", "");print $0+0}'

try also (using Scrutinizer's sed example) for eliminating leading non valid chars for numbers:

var=$(sed -n '$s/^[^1-9]*//p' infile)