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#1
11-30-2012
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Print all lines before first match
Hi, I have this file. Code:
close block3c block3b block3a open close block2b block2a open close block1a open and I need : Code:
open block3a block3b block3c close I think that it could be done with sed, but does anyone can help me with that? Thanks Last edited by Franklin52; 11-30-2012 at 05:46 AM.. Reason: Please use code tags for data and code samples |
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#2
11-30-2012
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Please use code tags for code and data sample. Code:
awk '/open/ && !a{a=NR}{A[NR]=$0}END{for(i=a;i>=1;i--){print A[i]}}' file |
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