My script(ksh) works fine for
---------------------------------------------------

sed -n '28,31p' ${l_name} >> ${LOG_DIR}/Email.txt

 grep -n '^bad' ${l_name}|read lstart 
 grep -n '^Statistics' ${l_name}|read lend

sed -n '$lstart,${lend}p' ${l_name} >> ${LOG_DIR}/Email.txt

Try it with double quotes(") so that the shell will expand the variable:

Code:

sed -n "${lstart},${lend}p" ${l_name} >> ${LOG_DIR}/Email.txt

Single quotes prevent parameter expansion. Use double quotes instead.
--
Bye

What are you actually trying to accomplish with the 2 grep commands? There might be better ways.

Double quote also didnt work

There is a log file i want to capture the portion between line 28 and 31 .

f_email()
{
  message "Sending  Bad record details  through Email "
  
  f_name=`ls -ltr ${BAD_FILE1} 2>/dev/null|awk '{print $9}'`
  l_name=`ls -ltr ${LOG_FILE1} 2>/dev/null|awk '{print $9}'`

  grep -n '^bad' ${l_name}|read lstart 
  grep -n '^Statistics' ${l_name}|read lend

echo "Please find the below reason for the rejection . To check the bad data plase find the attachment\n" > ${LOG_DIR}/Email.txt

#sed -n '28,31p' ${l_name} >> ${LOG_DIR}/Email.txt
sed -n "${lstart},${lend}p" ${l_name} >> ${LOG_DIR}/Email.txt

if [[ -s $f_name ]] then
    (cat ${LOG_DIR}/Email.txt;uuencode $f_name $f_name)|mailx -s "MFP SIZE Exceed report error" BalB@dressbarn.com
fi
}

head -31 sample.txt | tail -4

joeyg,
how to pass this 31 and 4 dynamically . these nos are not fix .
it may be 26 and 10