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#1
07-14-2005
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get yesterday in yyyymmdd format
how can i get yesterday in yyyymmdd format?
 
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#3
07-15-2005
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if you have issue with the above method say you dont have gnu date... try connecting to oracle and get date from there...as there is no direct mechanism to calculate date.
something like this ... Code:
yesterday=`sqlplus user/password << EOF Select to_char(sysdate-1,'YYYYMMDD') from dual Exit EOF`
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#4
07-15-2005
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I wrote this script to convert julian date into dd-mm-yyyy format. You could use this to get yesterday's date. You just have to get today's julian date (get this using `date +%j`) and subtract 1 from it. This will get you yesterday's julian date. Give this as the second argument to the script. The first argument is the present year in the YYYY format.
Note: I have changed the output so that it prints YYYYmmdd. [edit] Also this script will blindly convert whatever the julian date that is given to it. No error checking is done - so if you give the julian date as 0, the output you get for this year is 20050100 [/edit] Code:
#!/bin/sh
check_done() {
if [ $month -eq 1 -o $month -eq 3 -o $month -eq 5 -o $month -eq 7 -o $mo
nth -eq 8 -o $month -eq 10 -o $month -eq 12 ]
then
daysofmth=31
elif [ $month -eq 2 ]
then
if [ `expr $year % 100` -eq 0 -a `expr $year % 400` -eq 0 ]
then
daysofmth=29
elif [ `expr $year % 100` -ne 0 -a `expr $year % 4` -eq 0 ]
then
daysofmth=29
else
daysofmth=28
fi
elif [ $month -eq 4 -o $month -eq 6 -o $month -eq 9 -o $month -eq 11 ]
then
daysofmth=30
fi
julday=`expr $julday - $daysofmth`
if [ $julday -lt 0 ]
then
done=1
julday=`expr $daysofmth + $julday`
elif [ $julday -eq 0 ]
then
done=1
julday=$daysofmth
fi
}
######### main script starts here
if [ $# -ne 2 ]
then
echo "Usage: fromjul <yyyy> <julian day>"
exit 1
fi
year=$1
julday=$2
month=0
done=0
while [ $done -ne 1 ]
do
month=`expr $month + 1`
check_done
done
printf "%.4d%.2d%.2d\n" $year $month $julday
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#6
07-16-2005
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Code:
date | awk '{printf"%4d%2d%2d\n",$6,$2,($3-1)}' | sed 's/ /0/g'
here is the modification of the aboe one: date '+%y:%m:%d' | awk -F":" '{printf"20%2d%2d%2d\n",$1,$2,($3-1)}' | sed 's/ /0/g'
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