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07-14-2005
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awk / bash globbing question
I would like to process a list of files matching: GPS*\.xyz with an awk script. I would then like to output the files to GPS*\.xyz.out (e.g. the same file name appended with .out). Something like: Code:
awk '{if(NR==1) {offset=-$1}; $1=$1+offset; print }' GPS*.xyz
this does exactly what I want EXCEPT redirecting the output appropriately. I tried Code:
awk '{ ... print > FILENAME.out}' GPS*.xyz
and
awk '{...}' GPS*.xyz > GPS*.xyz.out
but as expected this did not work. I realize that putting this in: Code:
for f in ls GPS*.xyz loop would work as I need but I would like an elegant solution that I can learn from. Suggestions? Cheers, Brandon Franzke |
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07-14-2005
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Quote:
Code:
awk 'FNR==1 {offset=-$1;next} {$1+=offset; print >FILENAME".out"}' PS*.xyz
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07-15-2005
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Quote:
Code:
awk 'FNR==1 {offset=$1;close(f);f=FILENAME".out";next}{$1-=offset; print >f}' GPS*.xyz
The next is there becasue I assume you don't want the line with the offset to be printed. |
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